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70x^2-32x-10=-4
We move all terms to the left:
70x^2-32x-10-(-4)=0
We add all the numbers together, and all the variables
70x^2-32x-6=0
a = 70; b = -32; c = -6;
Δ = b2-4ac
Δ = -322-4·70·(-6)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-52}{2*70}=\frac{-20}{140} =-1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+52}{2*70}=\frac{84}{140} =3/5 $
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